Lab 20: Solubility: A Guided Inquiry Lab
During the Solubility Lab, my partner and I identified an unknown salt. The purpose of this lab was to design a procedure that determines the identify of the unknown salt. In the lab, we dissolved different amounts of the unknown salt with 10 mL of water at different temperatures. Dissolving is the process in which molecules interact and attract each other to form a solution.
Procedure -
First, we measured 100 mL of water in a beaker and increased the temperature from 20°C to 50°C using a hot plate. Then, we measured 5 g of the unknown salt on a balance. After that, we added the unknown salt to the to the water. All of the solute dissolved into the water. Realizing we made the mistake of having 100 mL of water instead of 10 mL of water, we measured 10 mL of water and increased the water temperature to 50°C. We added 5 g of the unknown salt. Only 3.9 g out of 5 g dissolved in the 10 mL of water. We concluded that the unknown salt was NaCl because 3.9 g of NaCl dissolves in water at 50°C.
Data -
Conclusion -
Overall, the lab was successful. The unknown salt was correctly identified as sodium chloride (NaCl). We knew this because 3.9 g of NaCl is the maximum amount of solute that can be dissolved in 10 mL of water at 50°C. If the unknown salt was any other substance, all 5 g of the solute would have dissolved in the 10 ml of 50°C water. We learned that as the temperature increases, the solubility increases too.
Procedure -
First, we measured 100 mL of water in a beaker and increased the temperature from 20°C to 50°C using a hot plate. Then, we measured 5 g of the unknown salt on a balance. After that, we added the unknown salt to the to the water. All of the solute dissolved into the water. Realizing we made the mistake of having 100 mL of water instead of 10 mL of water, we measured 10 mL of water and increased the water temperature to 50°C. We added 5 g of the unknown salt. Only 3.9 g out of 5 g dissolved in the 10 mL of water. We concluded that the unknown salt was NaCl because 3.9 g of NaCl dissolves in water at 50°C.
Data -
Overall, the lab was successful. The unknown salt was correctly identified as sodium chloride (NaCl). We knew this because 3.9 g of NaCl is the maximum amount of solute that can be dissolved in 10 mL of water at 50°C. If the unknown salt was any other substance, all 5 g of the solute would have dissolved in the 10 ml of 50°C water. We learned that as the temperature increases, the solubility increases too.
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